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标题: 树状菜单节点点击后在region框架打开网址，如何控制？ [打印本页]

作者: szjazz 时间: 2013-1-23 14:55
标题: 树状菜单节点点击后在region框架打开网址，如何控制？
本帖最后由 szjazz 于 2013-1-23 15:09 编辑

如何让树状菜单点击后，在右侧的regMain框架打开网址？

作者: 石头 时间: 2013-1-24 01:25
在javascript中写下如下代码：
  // Add a dynamic tab (With toolbar).
               var mainTabStrip = Ext.getCmp('<%= mainTabStrip.ClientID %>');
               var tabID = 'dynamic_added_tab' + node.id.replace('__', '-');
               mainTabStrip.addTab({
                  'id': tabID,
                  'url': href,
                  'title': node.parentNode.text + ' -> ' + node.text,
                  'closable': true,
                  'bodyStyle': 'padding:0px;',
                  'iconCls': 'icon_' + href.replace(/[^.]+\./, ''),
                  'tbar': new Ext.Toolbar({
                     items: ['->', sourcecodeButton,  '-', openNewWindowButton]
                  })
               });
         }

         // Click the tree node.
         treeMenu.on('click', function (node, event) {
               if (node.isLeaf()) {
                  var href = node.attributes.href;
                  // Modify the location of current url.
                  window.location.href = '#' + href;

                  addExampleTab(node);

                  // Don't response to this tree node's default behavior.
                  event.stopEvent();
               }
         });

         (function pageFirstLoad() {
               var currentHash = window.location.hash.substr(1);
               var level1Nodes = treeMenu.getRootNode().childNodes;
               for (var i = 0; i < level1Nodes.length; i++) {
                  var level2Nodes = level1Nodes[i].childNodes;
                  for (var j = 0; j < level2Nodes.length; j++) {
                     var currentNode = level2Nodes[j];
                     if (currentNode.attributes.href === currentHash) {
                           level1Nodes[i].expand();
                           // We must retrieve this node again, because currentNode doesn't has parentNode property.
                           var foundNode = treeMenu.getNodeById(currentNode.id);
                           foundNode.select();
                           addExampleTab(foundNode);
                           return;
                     }
                  }
               }
         })();

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